The Pendulum Problem

Thanks to @displaynameforrent for suggesting this Do note that it's also valid to arrive at this result from the equation of motion d2theta/dt2 + g/L sin(theta), with the stipulation instead that a=-gsin(theta). The only difference is that I've embedded the negative sign into g prior to the problem. The result will be a differential equation whose general solution is expressed in complex exponentials whose real component is equivalent to my solution (a sum of sines and cosines.) #Mathematics #Physics

To earn tokens and access the decentralized web, select an option below

(It's easier than you think)

We are an open source platform for Internet freedom. Get paid in crypto for your contributions to the community.

Maybe later